How to run .EXE on button click in C#

Simple Call: 

using System.Diagnostics;

This namespace provides access to local and remote processes and enables you to start and stop local system processes.

protected void Button1_Click(object sender, EventArgs e)
    {
       // string str = @"C:\windows\system32\notepad.exe";

       // string str  = @"C:\windows\system32\winamp.exe";

        string str  = @"C:\Documents and Settings\RAJ\Desktop\MCNewsLetter\SendNewsletter.exe";
        Process process = new Process();
        process.StartInfo.FileName = str;
        process.Start();

With Attributes:

using System.Diagnostics;
 class Program {
    static void Main()
    {
    LaunchCommandLineApp();
    }

    /// <summary>
    /// Launch the legacy application with some options set.
    /// </summary>
    static void LaunchCommandLineApp()
    {
    // For the example
    const string ex1 = "C:\\";
    const string ex2 = "C:\\Dir";

    // Use ProcessStartInfo class
    ProcessStartInfo startInfo = new ProcessStartInfo();
    startInfo.CreateNoWindow = false;
    startInfo.UseShellExecute = false;
    startInfo.FileName = "dcm2jpg.exe";
    startInfo.WindowStyle = ProcessWindowStyle.Hidden;
    startInfo.Arguments = "-f j -o \"" + ex1 + "\" -z 1.0 -s y " + ex2; 

startInfo.WorkingDirectory=@"C:\WD"

    try
    {
        // Start the process with the info we specified.
        // Call WaitForExit and then the using statement will close.
        using (Process exeProcess = Process.Start(startInfo))
        {
        exeProcess.WaitForExit(); 

        string status=exeProcess.HasExited; //returns process execution status
        }
    }
    catch
    {
        // Log error.
    }
    } }